铈钛复合氧化物催化CO还原SO2

来源期刊:中国有色金属学报(英文版)2016年第11期

论文作者:张丽 秦毅红 陈白珍 彭亚光 何汉兵 袁依

文章页码:2960 - 2965

关键词:铈钛复合氧化物;固溶体;催化还原;一氧化碳;二氧化硫

Key words:CeO2-TiO2 mixed oxides; solid solution; catalytic reduction; carbon monoxide; sulfur dioxide

摘    要:利用X射线衍射(XRD),X射线光电子能谱(XPS)及活性测试对铈钛复合氧化物的结构及催化脱硫特性进行了研究。结果表明:当铈-钛摩尔比(n(Ce)/n(Ti))≥5:5时,铈钛复合氧化物形成固溶体;当n(Ce)/n(Ti)=7:3(即Ce0.7Ti0.3O2)时,具有最佳的催化脱硫效果;500 °C下SO2的转化率达到93%,单质硫的产率达到99%。根据Ce0.7Ti0.3O2的活性测试曲线发现:未经预处理的Ce0.7Ti0.3O2约10 min后开始逐渐被反应气体活化,并在60 min后达到稳定活化状态。通过对不同反应时间下所得Ce0.7Ti0.3O2进行XPS分析发现: CeO2为活性物质,在反应过程中形成Ce4+/Ce3+氧化还原电对和活性氧空位,而TiO2仅起到稳定催化剂结构的作用。Ce0.7Ti0.3O2催化SO2+CO反应48 h后未出现硫化现象,始终保持结构的稳定,表现出较好的抗硫中毒性能。

Abstract: The structure and catalytic desulfurization characteristics of CeO2-TiO2 mixed oxides were investigated by means of X-ray diffraction (XRD), X-ray photoelectron spectroscopy (XPS) and catalytic activity tests. According to the results, a CeO2-TiO2 solid solution is formed when the mole ratio of cerium to titanium n(Ce):n(Ti) is 5:5 or greater, and the most suitable n(Ce):n(Ti) is determined as 7:3, over which the conversion rate of SO2 and the yield of sulfur at 500 °C reach 93% and 99%, respectively. According to the activity testing curve, Ce0.7Ti0.3O2 (n(Ce):n(Ti)=7:3) without any pretreatment can be gradually activated by reagent gas after about 10 min, and reaches a steady activation status 60 min later. The XPS results of Ce0.7Ti0.3O2 after different time of SO2+CO reaction show that CeO2 is the active component that offers the redox couple Ce4+/Ce3+ and the labile oxygen vacancies, and TiO2 only functions as a catalyst structure stabilizer during the catalytic reaction process. After 48 h of catalytic reaction at 500 °C, Ce0.7Ti0.3O2 still maintains a stable structure without being vulcanized, demonstrating its good anti-sulfur poisoning performance.

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